((3x^2)+1)(3x-2)=0

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Solution for ((3x^2)+1)(3x-2)=0 equation: 


Simplifying
((3x2) + 1)(3x + -2) = 0

Reorder the terms:
(1 + (3x2))(3x + -2) = 0

Reorder the terms:
(1 + (3x2))(-2 + 3x) = 0

Multiply (1 + (3x2)) * (-2 + 3x)
(1(-2 + 3x) + (3x2)(-2 + 3x)) = 0
((-2 * 1 + 3x * 1) + (3x2)(-2 + 3x)) = 0
((-2 + 3x) + (3x2)(-2 + 3x)) = 0
(-2 + 3x + (-2 * 3x2 + 3x * 3x2)) = 0
(-2 + 3x + (-6x2 + 9x3)) = 0
(-2 + 3x + -6x2 + 9x3) = 0

Solving
-2 + 3x + -6x2 + 9x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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